Solve for m 14m-10=3(4+m)

$14 m - 10 = 3 (4 + m)$

Step 1

Simplify $3 (4 + m)$ .

Rewrite.

$14 m - 10 = 0 + 0 + 3 (4 + m)$

Simplify by adding zeros.

$14 m - 10 = 3 (4 + m)$

Apply the distributive property.

$14 m - 10 = 3 \cdot 4 + 3 m$

Multiply $3$ by $4$ .

$14 m - 10 = 12 + 3 m$

Step 2

Move all terms containing $m$ to the left side of the equation.

Subtract $3 m$ from both sides of the equation.

$14 m - 10 - 3 m = 12$

Subtract $3 m$ from $14 m$ .

$11 m - 10 = 12$

Step 3

Move all terms not containing $m$ to the right side of the equation.

Add $10$ to both sides of the equation.

$11 m = 12 + 10$

Add $12$ and $10$ .

$11 m = 22$

Step 4

Divide each term in $11 m = 22$ by $11$ and simplify.

Divide each term in $11 m = 22$ by $11$ .

$\frac{11 m}{11} = \frac{22}{11}$

Simplify the left side.

Cancel the common factor of $11$ .

Cancel the common factor.

$\frac{11 m}{11} = \frac{22}{11}$

Divide $m$ by $1$ .

$m = \frac{22}{11}$

Simplify the right side.

Divide $22$ by $11$ .

$m = 2$