Solve for m 2* log of m = log of 36

$2 \cdot \log (m) = \log (36)$

Simplify $2 \cdot \log (m)$ by moving $2$ inside the logarithm.

$\log (m^{2}) = \log (36)$

For the equation to be equal, the argument of the logarithms on both sides of the equation must be equal.

$m^{2} = 36$

Solve for $m$ .

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$m = \pm \sqrt{36}$

Simplify $\pm \sqrt{36}$ .

Rewrite $36$ as $6^{2}$ .

$m = \pm \sqrt{6^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$m = \pm 6$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$m = 6$

Next, use the negative value of the $\pm$ to find the second solution.

$m = - 6$

The complete solution is the result of both the positive and negative portions of the solution.

$m = 6, - 6$

Exclude the solutions that do not make $2 \cdot \log (m) = \log (36)$ true.

$m = 6$