Solve for m 2(m-3)+7<21

$2 (m - 3) + 7 < 21$

Step 1

Simplify $2 (m - 3) + 7$ .

Simplify each term.

Apply the distributive property.

$2 m + 2 \cdot - 3 + 7 < 21$

Multiply $2$ by $- 3$ .

$2 m - 6 + 7 < 21$

Add $- 6$ and $7$ .

$2 m + 1 < 21$

Step 2

Move all terms not containing $m$ to the right side of the inequality.

Subtract $1$ from both sides of the inequality.

$2 m < 21 - 1$

Subtract $1$ from $21$ .

$2 m < 20$

Step 3

Divide each term in $2 m < 20$ by $2$ and simplify.

Divide each term in $2 m < 20$ by $2$ .

$\frac{2 m}{2} < \frac{20}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 m}{2} < \frac{20}{2}$

Divide $m$ by $1$ .

$m < \frac{20}{2}$

Simplify the right side.

Divide $20$ by $2$ .

$m < 10$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$m < 10$

Interval Notation:

$(- \infty, 10)$