Solve for m 25=-5+2/3m

$25 = - 5 + \frac{2}{3} m$

Step 1

Rewrite the equation as $- 5 + \frac{2}{3} m = 25$ .

$- 5 + \frac{2}{3} m = 25$

Step 2

Combine $\frac{2}{3}$ and $m$ .

$- 5 + \frac{2 m}{3} = 25$

Step 3

Move all terms not containing $m$ to the right side of the equation.

Add $5$ to both sides of the equation.

$\frac{2 m}{3} = 25 + 5$

Add $25$ and $5$ .

$\frac{2 m}{3} = 30$

Step 4

Multiply both sides of the equation by $\frac{3}{2}$ .

$\frac{3}{2} \cdot \frac{2 m}{3} = \frac{3}{2} \cdot 30$

Step 5

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{3}{2} \cdot \frac{2 m}{3}$ .

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3}{2} \cdot \frac{2 m}{3} = \frac{3}{2} \cdot 30$

Rewrite the expression.

$\frac{1}{2} (2 m) = \frac{3}{2} \cdot 30$

Cancel the common factor of $2$ .

Factor $2$ out of $2 m$ .

$\frac{1}{2} (2 (m)) = \frac{3}{2} \cdot 30$

Cancel the common factor.

$\frac{1}{2} (2 m) = \frac{3}{2} \cdot 30$

Rewrite the expression.

$m = \frac{3}{2} \cdot 30$

Simplify the right side.

Simplify $\frac{3}{2} \cdot 30$ .

Cancel the common factor of $2$ .

Factor $2$ out of $30$ .

$m = \frac{3}{2} \cdot (2 (15))$

Cancel the common factor.

$m = \frac{3}{2} \cdot (2 \cdot 15)$

Rewrite the expression.

$m = 3 \cdot 15$

Multiply $3$ by $15$ .

$m = 45$