Solve for m 2m^2+2/3m=0

$2 m^{2} + \frac{2}{3} m = 0$

Combine $\frac{2}{3}$ and $m$ .

$2 m^{2} + \frac{2 m}{3} = 0$

Factor $2 m$ out of $2 m^{2} + \frac{2 m}{3}$ .

Factor $2 m$ out of $2 m^{2}$ .

$2 m (m) + \frac{2 m}{3} = 0$

Factor $2 m$ out of $\frac{2 m}{3}$ .

$2 m (m) + 2 m (\frac{1}{3}) = 0$

Factor $2 m$ out of $2 m (m) + 2 m \frac{1}{3}$ .

$2 m (m + \frac{1}{3}) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$m = 0$

$m + \frac{1}{3} = 0$

Set $m$ equal to $0$ .

$m = 0$

Set $m + \frac{1}{3}$ equal to $0$ and solve for $m$ .

Set $m + \frac{1}{3}$ equal to $0$ .

$m + \frac{1}{3} = 0$

Subtract $\frac{1}{3}$ from both sides of the equation.

$m = - \frac{1}{3}$

The final solution is all the values that make $2 m (m + \frac{1}{3}) = 0$ true.

$m = 0, - \frac{1}{3}$

The result can be shown in multiple forms.

Exact Form:

$m = 0, - \frac{1}{3}$

Decimal Form:

$m = 0, - 0.\overline{3}$