Solve for m 2m+4(m-3)=7m-4

$2 m + 4 (m - 3) = 7 m - 4$

Step 1

Simplify $2 m + 4 (m - 3)$ .

Simplify each term.

Apply the distributive property.

$2 m + 4 m + 4 \cdot - 3 = 7 m - 4$

Multiply $4$ by $- 3$ .

$2 m + 4 m - 12 = 7 m - 4$

Add $2 m$ and $4 m$ .

$6 m - 12 = 7 m - 4$

Step 2

Move all terms containing $m$ to the left side of the equation.

Subtract $7 m$ from both sides of the equation.

$6 m - 12 - 7 m = - 4$

Subtract $7 m$ from $6 m$ .

$- m - 12 = - 4$

Step 3

Move all terms not containing $m$ to the right side of the equation.

Add $12$ to both sides of the equation.

$- m = - 4 + 12$

Add $- 4$ and $12$ .

$- m = 8$

Step 4

Divide each term in $- m = 8$ by $- 1$ and simplify.

Divide each term in $- m = 8$ by $- 1$ .

$\frac{- m}{- 1} = \frac{8}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{m}{1} = \frac{8}{- 1}$

Divide $m$ by $1$ .

$m = \frac{8}{- 1}$

Simplify the right side.

Divide $8$ by $- 1$ .

$m = - 8$