Solve for m (2m-7)/(3n)=3

$\frac{2 m - 7}{3 n} = 3$

Multiply both sides by $3 n$ .

$\frac{2 m - 7}{3 n} (3 n) = 3 (3 n)$

Simplify.

Simplify the left side.

Simplify $\frac{2 m - 7}{3 n} (3 n)$ .

Rewrite using the commutative property of multiplication.

$3 \frac{2 m - 7}{3 n} n = 3 (3 n)$

Cancel the common factor of $3$ .

Factor $3$ out of $3 n$ .

$3 \frac{2 m - 7}{3 (n)} n = 3 (3 n)$

Cancel the common factor.

$3 \frac{2 m - 7}{3 n} n = 3 (3 n)$

Rewrite the expression.

$\frac{2 m - 7}{n} n = 3 (3 n)$

Cancel the common factor of $n$ .

Cancel the common factor.

$\frac{2 m - 7}{n} n = 3 (3 n)$

Rewrite the expression.

$2 m - 7 = 3 (3 n)$

Simplify the right side.

Multiply $3$ by $3$ .

$2 m - 7 = 9 n$

Solve for $m$ .

Add $7$ to both sides of the equation.

$2 m = 9 n + 7$

Divide each term in $2 m = 9 n + 7$ by $2$ and simplify.

Divide each term in $2 m = 9 n + 7$ by $2$ .

$\frac{2 m}{2} = \frac{9 n}{2} + \frac{7}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 m}{2} = \frac{9 n}{2} + \frac{7}{2}$

Divide $m$ by $1$ .

$m = \frac{9 n}{2} + \frac{7}{2}$