Solve for m 3(10+2m)=96

$3 (10 + 2 m) = 96$

Step 1

Divide each term in $3 (10 + 2 m) = 96$ by $3$ and simplify.

Divide each term in $3 (10 + 2 m) = 96$ by $3$ .

$\frac{3 (10 + 2 m)}{3} = \frac{96}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (10 + 2 m)}{3} = \frac{96}{3}$

Divide $10 + 2 m$ by $1$ .

$10 + 2 m = \frac{96}{3}$

Simplify the right side.

Divide $96$ by $3$ .

$10 + 2 m = 32$

Step 2

Move all terms not containing $m$ to the right side of the equation.

Subtract $10$ from both sides of the equation.

$2 m = 32 - 10$

Subtract $10$ from $32$ .

$2 m = 22$

Step 3

Divide each term in $2 m = 22$ by $2$ and simplify.

Divide each term in $2 m = 22$ by $2$ .

$\frac{2 m}{2} = \frac{22}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 m}{2} = \frac{22}{2}$

Divide $m$ by $1$ .

$m = \frac{22}{2}$

Simplify the right side.

Divide $22$ by $2$ .

$m = 11$