Solve for m 3(2m-1)=4m+7

$3 (2 m - 1) = 4 m + 7$

Step 1

Simplify $3 (2 m - 1)$ .

Rewrite.

$0 + 0 + 3 (2 m - 1) = 4 m + 7$

Simplify by adding zeros.

$3 (2 m - 1) = 4 m + 7$

Apply the distributive property.

$3 (2 m) + 3 \cdot - 1 = 4 m + 7$

Multiply.

Multiply $2$ by $3$ .

$6 m + 3 \cdot - 1 = 4 m + 7$

Multiply $3$ by $- 1$ .

$6 m - 3 = 4 m + 7$

Step 2

Move all terms containing $m$ to the left side of the equation.

Subtract $4 m$ from both sides of the equation.

$6 m - 3 - 4 m = 7$

Subtract $4 m$ from $6 m$ .

$2 m - 3 = 7$

Step 3

Move all terms not containing $m$ to the right side of the equation.

Add $3$ to both sides of the equation.

$2 m = 7 + 3$

Add $7$ and $3$ .

$2 m = 10$

Step 4

Divide each term in $2 m = 10$ by $2$ and simplify.

Divide each term in $2 m = 10$ by $2$ .

$\frac{2 m}{2} = \frac{10}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 m}{2} = \frac{10}{2}$

Divide $m$ by $1$ .

$m = \frac{10}{2}$

Simplify the right side.

Divide $10$ by $2$ .

$m = 5$