Solve for m 3/4m>-12

$\frac{3}{4} m > - 12$

Multiply each term in $\frac{3}{4} m > - 12$ by $\frac{4}{3}$ .

$\frac{3}{4} m \frac{4}{3} > - 12 (\frac{4}{3})$

Simplify the left side.

Combine $\frac{3}{4}$ and $m$ .

$\frac{3 m}{4} \cdot \frac{4}{3} > - 12 (\frac{4}{3})$

Cancel the common factor of $3$ .

Factor $3$ out of $3 m$ .

$\frac{3 (m)}{4} \cdot \frac{4}{3} > - 12 (\frac{4}{3})$

Cancel the common factor.

$\frac{3 m}{4} \cdot \frac{4}{3} > - 12 (\frac{4}{3})$

Rewrite the expression.

$\frac{m}{4} \cdot 4 > - 12 (\frac{4}{3})$

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{m}{4} \cdot 4 > - 12 (\frac{4}{3})$

Rewrite the expression.

$m > - 12 (\frac{4}{3})$

Simplify the right side.

Cancel the common factor of $3$ .

Factor $3$ out of $- 12$ .

$m > 3 (- 4) \frac{4}{3}$

Cancel the common factor.

$m > 3 \cdot - 4 \frac{4}{3}$

Rewrite the expression.

$m > - 4 \cdot 4$

Multiply $- 4$ by $4$ .

$m > - 16$

The result can be shown in multiple forms.

Inequality Form:

$m > - 16$

Interval Notation:

$(- 16, \infty)$