Solve for m 5m+10p=20n

$5 m + 10 p = 20 n$

Step 1

Subtract $10 p$ from both sides of the equation.

$5 m = 20 n - 10 p$

Step 2

Divide each term in $5 m = 20 n - 10 p$ by $5$ and simplify.

Divide each term in $5 m = 20 n - 10 p$ by $5$ .

$\frac{5 m}{5} = \frac{20 n}{5} + \frac{- 10 p}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 m}{5} = \frac{20 n}{5} + \frac{- 10 p}{5}$

Divide $m$ by $1$ .

$m = \frac{20 n}{5} + \frac{- 10 p}{5}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $20$ and $5$ .

Factor $5$ out of $20 n$ .

$m = \frac{5 (4 n)}{5} + \frac{- 10 p}{5}$

Cancel the common factors.

Factor $5$ out of $5$ .

$m = \frac{5 (4 n)}{5 (1)} + \frac{- 10 p}{5}$

Cancel the common factor.

$m = \frac{5 (4 n)}{5 \cdot 1} + \frac{- 10 p}{5}$

Rewrite the expression.

$m = \frac{4 n}{1} + \frac{- 10 p}{5}$

Divide $4 n$ by $1$ .

$m = 4 n + \frac{- 10 p}{5}$

Cancel the common factor of $- 10$ and $5$ .

Factor $5$ out of $- 10 p$ .

$m = 4 n + \frac{5 (- 2 p)}{5}$

Cancel the common factors.

Factor $5$ out of $5$ .

$m = 4 n + \frac{5 (- 2 p)}{5 (1)}$

Cancel the common factor.

$m = 4 n + \frac{5 (- 2 p)}{5 \cdot 1}$

Rewrite the expression.

$m = 4 n + \frac{- 2 p}{1}$

Divide $- 2 p$ by $1$ .

$m = 4 n - 2 p$