Solve for m (5m)/-7+8=3

$\frac{5 m}{- 7} + 8 = 3$

Step 1

Move the negative in front of the fraction.

$- \frac{5 m}{7} + 8 = 3$

Step 2

Move all terms not containing $m$ to the right side of the equation.

Subtract $8$ from both sides of the equation.

$- \frac{5 m}{7} = 3 - 8$

Subtract $8$ from $3$ .

$- \frac{5 m}{7} = - 5$

Step 3

Multiply both sides of the equation by $- \frac{7}{5}$ .

$- \frac{7}{5} (- \frac{5 m}{7}) = - \frac{7}{5} \cdot - 5$

Step 4

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{7}{5} (- \frac{5 m}{7})$ .

Cancel the common factor of $7$ .

Move the leading negative in $- \frac{7}{5}$ into the numerator.

$\frac{- 7}{5} (- \frac{5 m}{7}) = - \frac{7}{5} \cdot - 5$

Move the leading negative in $- \frac{5 m}{7}$ into the numerator.

$\frac{- 7}{5} \cdot \frac{- 5 m}{7} = - \frac{7}{5} \cdot - 5$

Factor $7$ out of $- 7$ .

$\frac{7 (- 1)}{5} \cdot \frac{- 5 m}{7} = - \frac{7}{5} \cdot - 5$

Cancel the common factor.

$\frac{7 \cdot - 1}{5} \cdot \frac{- 5 m}{7} = - \frac{7}{5} \cdot - 5$

Rewrite the expression.

$\frac{- 1}{5} (- 5 m) = - \frac{7}{5} \cdot - 5$

Cancel the common factor of $5$ .

Factor $5$ out of $- 5 m$ .

$\frac{- 1}{5} (5 (- m)) = - \frac{7}{5} \cdot - 5$

Cancel the common factor.

$\frac{- 1}{5} (5 (- m)) = - \frac{7}{5} \cdot - 5$

Rewrite the expression.

$- - m = - \frac{7}{5} \cdot - 5$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 m = - \frac{7}{5} \cdot - 5$

Multiply $m$ by $1$ .

$m = - \frac{7}{5} \cdot - 5$

Simplify the right side.

Simplify $- \frac{7}{5} \cdot - 5$ .

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{7}{5}$ into the numerator.

$m = \frac{- 7}{5} \cdot - 5$

Factor $5$ out of $- 5$ .

$m = \frac{- 7}{5} \cdot (5 (- 1))$

Cancel the common factor.

$m = \frac{- 7}{5} \cdot (5 \cdot - 1)$

Rewrite the expression.

$m = - 7 \cdot - 1$

Multiply $- 7$ by $- 1$ .

$m = 7$

Solve for m (5m)/-7+8=3

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