Solve for m 6(2m-3)-3m=2m-18+m

$6 (2 m - 3) - 3 m = 2 m - 18 + m$

Step 1

Simplify $6 (2 m - 3) - 3 m$ .

Simplify each term.

Apply the distributive property.

$6 (2 m) + 6 \cdot - 3 - 3 m = 2 m - 18 + m$

Multiply $2$ by $6$ .

$12 m + 6 \cdot - 3 - 3 m = 2 m - 18 + m$

Multiply $6$ by $- 3$ .

$12 m - 18 - 3 m = 2 m - 18 + m$

Subtract $3 m$ from $12 m$ .

$9 m - 18 = 2 m - 18 + m$

Step 2

Add $2 m$ and $m$ .

$9 m - 18 = 3 m - 18$

Step 3

Move all terms containing $m$ to the left side of the equation.

Subtract $3 m$ from both sides of the equation.

$9 m - 18 - 3 m = - 18$

Subtract $3 m$ from $9 m$ .

$6 m - 18 = - 18$

Step 4

Move all terms not containing $m$ to the right side of the equation.

Add $18$ to both sides of the equation.

$6 m = - 18 + 18$

Add $- 18$ and $18$ .

$6 m = 0$

Step 5

Divide each term in $6 m = 0$ by $6$ and simplify.

Divide each term in $6 m = 0$ by $6$ .

$\frac{6 m}{6} = \frac{0}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 m}{6} = \frac{0}{6}$

Divide $m$ by $1$ .

$m = \frac{0}{6}$

Simplify the right side.

Divide $0$ by $6$ .

$m = 0$