Solve for m (6m+6)=(14m-2)

$(6 m + 6) = (14 m - 2)$

Move all terms containing $m$ to the left side of the equation.

Subtract $14 m$ from both sides of the equation.

$6 m + 6 - 14 m = - 2$

Subtract $14 m$ from $6 m$ .

$- 8 m + 6 = - 2$

Move all terms not containing $m$ to the right side of the equation.

Subtract $6$ from both sides of the equation.

$- 8 m = - 2 - 6$

Subtract $6$ from $- 2$ .

$- 8 m = - 8$

Divide each term in $- 8 m = - 8$ by $- 8$ and simplify.

Divide each term in $- 8 m = - 8$ by $- 8$ .

$\frac{- 8 m}{- 8} = \frac{- 8}{- 8}$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 m}{- 8} = \frac{- 8}{- 8}$

Divide $m$ by $1$ .

$m = \frac{- 8}{- 8}$

Simplify the right side.

Divide $- 8$ by $- 8$ .

$m = 1$