Solve for m 6m-8=6(m+1)+2

$6 m - 8 = 6 (m + 1) + 2$

Step 1

Simplify $6 (m + 1) + 2$ .

Simplify each term.

Apply the distributive property.

$6 m - 8 = 6 m + 6 \cdot 1 + 2$

Multiply $6$ by $1$ .

$6 m - 8 = 6 m + 6 + 2$

Add $6$ and $2$ .

$6 m - 8 = 6 m + 8$

Step 2

Move all terms containing $m$ to the left side of the equation.

Subtract $6 m$ from both sides of the equation.

$6 m - 8 - 6 m = 8$

Combine the opposite terms in $6 m - 8 - 6 m$ .

Subtract $6 m$ from $6 m$ .

$0 - 8 = 8$

Subtract $8$ from $0$ .

$- 8 = 8$

Step 3

Since $- 8 \neq 8$ , there are no solutions.

No solution