Solve for m (8m-1)(m-4)=0

$(8 m - 1) (m - 4) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$8 m - 1 = 0$

$m - 4 = 0$

Set $8 m - 1$ equal to $0$ and solve for $m$ .

Set $8 m - 1$ equal to $0$ .

$8 m - 1 = 0$

Solve $8 m - 1 = 0$ for $m$ .

Add $1$ to both sides of the equation.

$8 m = 1$

Divide each term in $8 m = 1$ by $8$ and simplify.

Divide each term in $8 m = 1$ by $8$ .

$\frac{8 m}{8} = \frac{1}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 m}{8} = \frac{1}{8}$

Divide $m$ by $1$ .

$m = \frac{1}{8}$

Set $m - 4$ equal to $0$ and solve for $m$ .

Set $m - 4$ equal to $0$ .

$m - 4 = 0$

Add $4$ to both sides of the equation.

$m = 4$

The final solution is all the values that make $(8 m - 1) (m - 4) = 0$ true.

$m = \frac{1}{8}, 4$

The result can be shown in multiple forms.

Exact Form:

$m = \frac{1}{8}, 4$

Decimal Form:

$m = 0.125, 4$