Solve for m 8m+12=2(4m+6)

$8 m + 12 = 2 (4 m + 6)$

Simplify $2 (4 m + 6)$ .

Rewrite.

$8 m + 12 = 0 + 0 + 2 (4 m + 6)$

Simplify by adding zeros.

$8 m + 12 = 2 (4 m + 6)$

Apply the distributive property.

$8 m + 12 = 2 (4 m) + 2 \cdot 6$

Multiply.

Multiply $4$ by $2$ .

$8 m + 12 = 8 m + 2 \cdot 6$

Multiply $2$ by $6$ .

$8 m + 12 = 8 m + 12$

Move all terms containing $m$ to the left side of the equation.

Subtract $8 m$ from both sides of the equation.

$8 m + 12 - 8 m = 12$

Combine the opposite terms in $8 m + 12 - 8 m$ .

Subtract $8 m$ from $8 m$ .

$0 + 12 = 12$

Add $0$ and $12$ .

$12 = 12$

Since $12 = 12$ , the equation will always be true for any value of $m$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$