Solve for m -9=2/5m+7

$- 9 = \frac{2}{5} m + 7$

Step 1

Rewrite the equation as $\frac{2}{5} m + 7 = - 9$ .

$\frac{2}{5} m + 7 = - 9$

Step 2

Combine $\frac{2}{5}$ and $m$ .

$\frac{2 m}{5} + 7 = - 9$

Step 3

Move all terms not containing $m$ to the right side of the equation.

Subtract $7$ from both sides of the equation.

$\frac{2 m}{5} = - 9 - 7$

Subtract $7$ from $- 9$ .

$\frac{2 m}{5} = - 16$

Step 4

Multiply both sides of the equation by $\frac{5}{2}$ .

$\frac{5}{2} \cdot \frac{2 m}{5} = \frac{5}{2} \cdot - 16$

Step 5

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{5}{2} \cdot \frac{2 m}{5}$ .

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5}{2} \cdot \frac{2 m}{5} = \frac{5}{2} \cdot - 16$

Rewrite the expression.

$\frac{1}{2} (2 m) = \frac{5}{2} \cdot - 16$

Cancel the common factor of $2$ .

Factor $2$ out of $2 m$ .

$\frac{1}{2} (2 (m)) = \frac{5}{2} \cdot - 16$

Cancel the common factor.

$\frac{1}{2} (2 m) = \frac{5}{2} \cdot - 16$

Rewrite the expression.

$m = \frac{5}{2} \cdot - 16$

Simplify the right side.

Simplify $\frac{5}{2} \cdot - 16$ .

Cancel the common factor of $2$ .

Factor $2$ out of $- 16$ .

$m = \frac{5}{2} \cdot (2 (- 8))$

Cancel the common factor.

$m = \frac{5}{2} \cdot (2 \cdot - 8)$

Rewrite the expression.

$m = 5 \cdot - 8$

Multiply $5$ by $- 8$ .

$m = - 40$