Solve for m 9(m-3)+3m=7m+43

$9 (m - 3) + 3 m = 7 m + 43$

Simplify $9 (m - 3) + 3 m$ .

Simplify each term.

Apply the distributive property.

$9 m + 9 \cdot - 3 + 3 m = 7 m + 43$

Multiply $9$ by $- 3$ .

$9 m - 27 + 3 m = 7 m + 43$

Add $9 m$ and $3 m$ .

$12 m - 27 = 7 m + 43$

Move all terms containing $m$ to the left side of the equation.

Subtract $7 m$ from both sides of the equation.

$12 m - 27 - 7 m = 43$

Subtract $7 m$ from $12 m$ .

$5 m - 27 = 43$

Move all terms not containing $m$ to the right side of the equation.

Add $27$ to both sides of the equation.

$5 m = 43 + 27$

Add $43$ and $27$ .

$5 m = 70$

Divide each term in $5 m = 70$ by $5$ and simplify.

Divide each term in $5 m = 70$ by $5$ .

$\frac{5 m}{5} = \frac{70}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 m}{5} = \frac{70}{5}$

Divide $m$ by $1$ .

$m = \frac{70}{5}$

Simplify the right side.

Divide $70$ by $5$ .

$m = 14$