Solve for m 9m-(6m-7)=2(m-3)

$9 m - (6 m - 7) = 2 (m - 3)$

Step 1

Simplify $9 m - (6 m - 7)$ .

Simplify each term.

Apply the distributive property.

$9 m - (6 m) - - 7 = 2 (m - 3)$

Multiply $6$ by $- 1$ .

$9 m - 6 m - - 7 = 2 (m - 3)$

Multiply $- 1$ by $- 7$ .

$9 m - 6 m + 7 = 2 (m - 3)$

Subtract $6 m$ from $9 m$ .

$3 m + 7 = 2 (m - 3)$

Step 2

Simplify $2 (m - 3)$ .

Apply the distributive property.

$3 m + 7 = 2 m + 2 \cdot - 3$

Multiply $2$ by $- 3$ .

$3 m + 7 = 2 m - 6$

Step 3

Move all terms containing $m$ to the left side of the equation.

Subtract $2 m$ from both sides of the equation.

$3 m + 7 - 2 m = - 6$

Subtract $2 m$ from $3 m$ .

$m + 7 = - 6$

Step 4

Move all terms not containing $m$ to the right side of the equation.

Subtract $7$ from both sides of the equation.

$m = - 6 - 7$

Subtract $7$ from $- 6$ .

$m = - 13$