Solve for m k=2mn+2ml

$k = 2 m n + 2 m l$

Step 1

Rewrite the equation as $2 m n + 2 m l = k$ .

$2 m n + 2 m l = k$

Step 2

Factor $2 m$ out of $2 m n + 2 m l$ .

Factor $2 m$ out of $2 m n$ .

$2 m (n) + 2 m l = k$

Factor $2 m$ out of $2 m l$ .

$2 m (n) + 2 m (l) = k$

Factor $2 m$ out of $2 m (n) + 2 m (l)$ .

$2 m (n + l) = k$

Step 3

Divide each term in $2 m (n + l) = k$ by $2 (n + l)$ and simplify.

Divide each term in $2 m (n + l) = k$ by $2 (n + l)$ .

$\frac{2 m (n + l)}{2 (n + l)} = \frac{k}{2 (n + l)}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 m (n + l)}{2 (n + l)} = \frac{k}{2 (n + l)}$

Rewrite the expression.

$\frac{m (n + l)}{n + l} = \frac{k}{2 (n + l)}$

Cancel the common factor of $n + l$ .

Cancel the common factor.

$\frac{m (n + l)}{n + l} = \frac{k}{2 (n + l)}$

Divide $m$ by $1$ .

$m = \frac{k}{2 (n + l)}$