Solve for m m^2=2m

$m^{2} = 2 m$

Subtract $2 m$ from both sides of the equation.

$m^{2} - 2 m = 0$

Factor $m$ out of $m^{2} - 2 m$ .

Factor $m$ out of $m^{2}$ .

$m \cdot m - 2 m = 0$

Factor $m$ out of $- 2 m$ .

$m \cdot m + m \cdot - 2 = 0$

Factor $m$ out of $m \cdot m + m \cdot - 2$ .

$m (m - 2) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$m = 0$

$m - 2 = 0$

Set $m$ equal to $0$ .

$m = 0$

Set $m - 2$ equal to $0$ and solve for $m$ .

Set $m - 2$ equal to $0$ .

$m - 2 = 0$

Add $2$ to both sides of the equation.

$m = 2$

The final solution is all the values that make $m (m - 2) = 0$ true.

$m = 0, 2$