Solve for n 10(5-n)-1=29

$10 (5 - n) - 1 = 29$

Simplify $10 (5 - n) - 1$ .

Simplify each term.

Apply the distributive property.

$10 \cdot 5 + 10 (- n) - 1 = 29$

Multiply $10$ by $5$ .

$50 + 10 (- n) - 1 = 29$

Multiply $- 1$ by $10$ .

$50 - 10 n - 1 = 29$

Subtract $1$ from $50$ .

$- 10 n + 49 = 29$

Move all terms not containing $n$ to the right side of the equation.

Subtract $49$ from both sides of the equation.

$- 10 n = 29 - 49$

Subtract $49$ from $29$ .

$- 10 n = - 20$

Divide each term in $- 10 n = - 20$ by $- 10$ and simplify.

Divide each term in $- 10 n = - 20$ by $- 10$ .

$\frac{- 10 n}{- 10} = \frac{- 20}{- 10}$

Simplify the left side.

Cancel the common factor of $- 10$ .

Cancel the common factor.

$\frac{- 10 n}{- 10} = \frac{- 20}{- 10}$

Divide $n$ by $1$ .

$n = \frac{- 20}{- 10}$

Simplify the right side.

Divide $- 20$ by $- 10$ .

$n = 2$