Solve for n 16-2n=-8+4(n-3)

$16 - 2 n = - 8 + 4 (n - 3)$

Step 1

Simplify $- 8 + 4 (n - 3)$ .

Simplify each term.

Apply the distributive property.

$16 - 2 n = - 8 + 4 n + 4 \cdot - 3$

Multiply $4$ by $- 3$ .

$16 - 2 n = - 8 + 4 n - 12$

Subtract $12$ from $- 8$ .

$16 - 2 n = 4 n - 20$

Step 2

Move all terms containing $n$ to the left side of the equation.

Subtract $4 n$ from both sides of the equation.

$16 - 2 n - 4 n = - 20$

Subtract $4 n$ from $- 2 n$ .

$16 - 6 n = - 20$

Step 3

Move all terms not containing $n$ to the right side of the equation.

Subtract $16$ from both sides of the equation.

$- 6 n = - 20 - 16$

Subtract $16$ from $- 20$ .

$- 6 n = - 36$

Step 4

Divide each term in $- 6 n = - 36$ by $- 6$ and simplify.

Divide each term in $- 6 n = - 36$ by $- 6$ .

$\frac{- 6 n}{- 6} = \frac{- 36}{- 6}$

Simplify the left side.

Cancel the common factor of $- 6$ .

Cancel the common factor.

$\frac{- 6 n}{- 6} = \frac{- 36}{- 6}$

Divide $n$ by $1$ .

$n = \frac{- 36}{- 6}$

Simplify the right side.

Divide $- 36$ by $- 6$ .

$n = 6$