Solve for n 180(n-2)=s

$180 (n - 2) = s$

Divide each term in $180 (n - 2) = s$ by $180$ and simplify.

Divide each term in $180 (n - 2) = s$ by $180$ .

$\frac{180 (n - 2)}{180} = \frac{s}{180}$

Simplify the left side.

Cancel the common factor of $180$ .

Cancel the common factor.

$\frac{180 (n - 2)}{180} = \frac{s}{180}$

Divide $n - 2$ by $1$ .

$n - 2 = \frac{s}{180}$

Add $2$ to both sides of the equation.

$n = \frac{s}{180} + 2$