Solve for n (2n-3)/5=5

$\frac{2 n - 3}{5} = 5$

Step 1

Multiply both sides by $5$ .

$\frac{2 n - 3}{5} \cdot 5 = 5 \cdot 5$

Step 2

Simplify.

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{2 n - 3}{5} \cdot 5 = 5 \cdot 5$

Rewrite the expression.

$2 n - 3 = 5 \cdot 5$

Simplify the right side.

Multiply $5$ by $5$ .

$2 n - 3 = 25$

Step 3

Solve for $n$ .

Move all terms not containing $n$ to the right side of the equation.

Add $3$ to both sides of the equation.

$2 n = 25 + 3$

Add $25$ and $3$ .

$2 n = 28$

Divide each term in $2 n = 28$ by $2$ and simplify.

Divide each term in $2 n = 28$ by $2$ .

$\frac{2 n}{2} = \frac{28}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 n}{2} = \frac{28}{2}$

Divide $n$ by $1$ .

$n = \frac{28}{2}$

Simplify the right side.

Divide $28$ by $2$ .

$n = 14$