Solve for n 2n=4x+2y

$2 n = 4 x + 2 y$

Step 1

Divide each term in $2 n = 4 x + 2 y$ by $2$ .

$\frac{2 n}{2} = \frac{4 x}{2} + \frac{2 y}{2}$

Step 2

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 n}{2} = \frac{4 x}{2} + \frac{2 y}{2}$

Divide $n$ by $1$ .

$n = \frac{4 x}{2} + \frac{2 y}{2}$

$n = \frac{4 x}{2} + \frac{2 y}{2}$

$n = \frac{4 x}{2} + \frac{2 y}{2}$

Step 3

Simplify the right side.

Simplify each term.

Cancel the common factor of $4$ and $2$ .

Factor $2$ out of $4 x$ .

$n = \frac{2 (2 x)}{2} + \frac{2 y}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$n = \frac{2 (2 x)}{2 (1)} + \frac{2 y}{2}$

Cancel the common factor.

$n = \frac{2 (2 x)}{2 \cdot 1} + \frac{2 y}{2}$

Rewrite the expression.

$n = \frac{2 x}{1} + \frac{2 y}{2}$

Divide $2 x$ by $1$ .

$n = 2 x + \frac{2 y}{2}$

$n = 2 x + \frac{2 y}{2}$

$n = 2 x + \frac{2 y}{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$n = 2 x + \frac{2 y}{2}$

Divide $y$ by $1$ .

$n = 2 x + y$

$n = 2 x + y$

$n = 2 x + y$

$n = 2 x + y$

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