Solve for n -3(4-2n)=-3(-1-3n)

$- 3 (4 - 2 n) = - 3 (- 1 - 3 n)$

Simplify $- 3 (4 - 2 n)$ .

Start simplifying.

$0 + 0 - 3 (4 - 2 n) = - 3 (- 1 - 3 n)$

Simplify by adding zeros.

$- 3 (4 - 2 n) = - 3 (- 1 - 3 n)$

Apply the distributive property.

$- 3 \cdot 4 - 3 (- 2 n) = - 3 (- 1 - 3 n)$

Multiply.

Multiply $- 3$ by $4$ .

$- 12 - 3 (- 2 n) = - 3 (- 1 - 3 n)$

Multiply $- 2$ by $- 3$ .

$- 12 + 6 n = - 3 (- 1 - 3 n)$

Simplify $- 3 (- 1 - 3 n)$ .

Apply the distributive property.

$- 12 + 6 n = - 3 \cdot - 1 - 3 (- 3 n)$

Multiply.

Multiply $- 3$ by $- 1$ .

$- 12 + 6 n = 3 - 3 (- 3 n)$

Multiply $- 3$ by $- 3$ .

$- 12 + 6 n = 3 + 9 n$

Move all terms containing $n$ to the left side of the equation.

Subtract $9 n$ from both sides of the equation.

$- 12 + 6 n - 9 n = 3$

Subtract $9 n$ from $6 n$ .

$- 12 - 3 n = 3$

Move all terms not containing $n$ to the right side of the equation.

Add $12$ to both sides of the equation.

$- 3 n = 3 + 12$

Add $3$ and $12$ .

$- 3 n = 15$

Divide each term in $- 3 n = 15$ by $- 3$ and simplify.

Divide each term in $- 3 n = 15$ by $- 3$ .

$\frac{- 3 n}{- 3} = \frac{15}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 n}{- 3} = \frac{15}{- 3}$

Divide $n$ by $1$ .

$n = \frac{15}{- 3}$

Simplify the right side.

Divide $15$ by $- 3$ .

$n = - 5$