Solve for n 3+4n+n=2n+15

$3 + 4 n + n = 2 n + 15$

Step 1

Add $4 n$ and $n$ .

$3 + 5 n = 2 n + 15$

Step 2

Move all terms containing $n$ to the left side of the equation.

Subtract $2 n$ from both sides of the equation.

$3 + 5 n - 2 n = 15$

Subtract $2 n$ from $5 n$ .

$3 + 3 n = 15$

Step 3

Move all terms not containing $n$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$3 n = 15 - 3$

Subtract $3$ from $15$ .

$3 n = 12$

Step 4

Divide each term in $3 n = 12$ by $3$ and simplify.

Divide each term in $3 n = 12$ by $3$ .

$\frac{3 n}{3} = \frac{12}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 n}{3} = \frac{12}{3}$

Divide $n$ by $1$ .

$n = \frac{12}{3}$

Simplify the right side.

Divide $12$ by $3$ .

$n = 4$