Solve for n 3/8+n=7/8

$\frac{3}{8} + n = \frac{7}{8}$

Subtract $\frac{3}{8}$ from both sides of the equation.

$n = \frac{7}{8} - \frac{3}{8}$

Combine the numerators over the common denominator.

$n = \frac{7 - 3}{8}$

Subtract $3$ from $7$ .

$n = \frac{4}{8}$

Cancel the common factor of $4$ and $8$ .

Factor $4$ out of $4$ .

$n = \frac{4 (1)}{8}$

Cancel the common factors.

Factor $4$ out of $8$ .

$n = \frac{4 \cdot 1}{4 \cdot 2}$

Cancel the common factor.

$n = \frac{4 \cdot 1}{4 \cdot 2}$

Rewrite the expression.

$n = \frac{1}{2}$

The result can be shown in multiple forms.

Exact Form:

$n = \frac{1}{2}$

Decimal Form:

$n = 0.5$