Solve for n -3(m-2n-4)=-9

$- 3 (m - 2 n - 4) = - 9$

Step 1

Divide each term in $- 3 (m - 2 n - 4) = - 9$ by $- 3$ and simplify.

Divide each term in $- 3 (m - 2 n - 4) = - 9$ by $- 3$ .

$\frac{- 3 (m - 2 n - 4)}{- 3} = \frac{- 9}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 (m - 2 n - 4)}{- 3} = \frac{- 9}{- 3}$

Divide $m - 2 n - 4$ by $1$ .

$m - 2 n - 4 = \frac{- 9}{- 3}$

Simplify the right side.

Divide $- 9$ by $- 3$ .

$m - 2 n - 4 = 3$

Step 2

Move all terms not containing $n$ to the right side of the equation.

Subtract $m$ from both sides of the equation.

$- 2 n - 4 = 3 - m$

Add $4$ to both sides of the equation.

$- 2 n = 3 - m + 4$

Add $3$ and $4$ .

$- 2 n = - m + 7$

Step 3

Divide each term in $- 2 n = - m + 7$ by $- 2$ and simplify.

Divide each term in $- 2 n = - m + 7$ by $- 2$ .

$\frac{- 2 n}{- 2} = \frac{- m}{- 2} + \frac{7}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 n}{- 2} = \frac{- m}{- 2} + \frac{7}{- 2}$

Divide $n$ by $1$ .

$n = \frac{- m}{- 2} + \frac{7}{- 2}$

Simplify the right side.

Simplify each term.

Dividing two negative values results in a positive value.

$n = \frac{m}{2} + \frac{7}{- 2}$

Move the negative in front of the fraction.

$n = \frac{m}{2} - \frac{7}{2}$