Solve for n -3(n+8)-4=-40-n

$- 3 (n + 8) - 4 = - 40 - n$

Step 1

Simplify $- 3 (n + 8) - 4$ .

Simplify each term.

Apply the distributive property.

$- 3 n - 3 \cdot 8 - 4 = - 40 - n$

Multiply $- 3$ by $8$ .

$- 3 n - 24 - 4 = - 40 - n$

Subtract $4$ from $- 24$ .

$- 3 n - 28 = - 40 - n$

Step 2

Move all terms containing $n$ to the left side of the equation.

Add $n$ to both sides of the equation.

$- 3 n - 28 + n = - 40$

Add $- 3 n$ and $n$ .

$- 2 n - 28 = - 40$

Step 3

Move all terms not containing $n$ to the right side of the equation.

Add $28$ to both sides of the equation.

$- 2 n = - 40 + 28$

Add $- 40$ and $28$ .

$- 2 n = - 12$

Step 4

Divide each term in $- 2 n = - 12$ by $- 2$ and simplify.

Divide each term in $- 2 n = - 12$ by $- 2$ .

$\frac{- 2 n}{- 2} = \frac{- 12}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 n}{- 2} = \frac{- 12}{- 2}$

Divide $n$ by $1$ .

$n = \frac{- 12}{- 2}$

Simplify the right side.

Divide $- 12$ by $- 2$ .

$n = 6$