Solve for n -3n-(8n-7)=n-(n+4)

$- 3 n - (8 n - 7) = n - (n + 4)$

Step 1

Simplify $- 3 n - (8 n - 7)$ .

Rewrite.

$- 3 n - (8 n - 7) - n + n = n - (n + 4)$

Simplify by adding terms.

$- 3 n - (8 n - 7) = n - (n + 4)$

Simplify each term.

Apply the distributive property.

$- 3 n - (8 n) - - 7 = n - (n + 4)$

Multiply $8$ by $- 1$ .

$- 3 n - 8 n - - 7 = n - (n + 4)$

Multiply $- 1$ by $- 7$ .

$- 3 n - 8 n + 7 = n - (n + 4)$

Subtract $8 n$ from $- 3 n$ .

$- 11 n + 7 = n - (n + 4)$

Step 2

Simplify $n - (n + 4)$ .

Simplify each term.

Apply the distributive property.

$- 11 n + 7 = n - n - 1 \cdot 4$

Multiply $- 1$ by $4$ .

$- 11 n + 7 = n - n - 4$

Simplify by adding terms.

Subtract $n$ from $n$ .

$- 11 n + 7 = 0 - 4$

Subtract $4$ from $0$ .

$- 11 n + 7 = - 4$

Step 3

Move all terms not containing $n$ to the right side of the equation.

Subtract $7$ from both sides of the equation.

$- 11 n = - 4 - 7$

Subtract $7$ from $- 4$ .

$- 11 n = - 11$

Step 4

Divide each term in $- 11 n = - 11$ by $- 11$ and simplify.

Divide each term in $- 11 n = - 11$ by $- 11$ .

$\frac{- 11 n}{- 11} = \frac{- 11}{- 11}$

Simplify the left side.

Cancel the common factor of $- 11$ .

Cancel the common factor.

$\frac{- 11 n}{- 11} = \frac{- 11}{- 11}$

Divide $n$ by $1$ .

$n = \frac{- 11}{- 11}$

Simplify the right side.

Divide $- 11$ by $- 11$ .

$n = 1$

Solve for n -3n-(8n-7)=n-(n+4)

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