Solve for n -4(3+n)>-32

$- 4 (3 + n) > - 32$

Step 1

Divide each term in $- 4 (3 + n) > - 32$ by $- 4$ and simplify.

Divide each term in $- 4 (3 + n) > - 32$ by $- 4$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 4 (3 + n)}{- 4} < \frac{- 32}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 (3 + n)}{- 4} < \frac{- 32}{- 4}$

Divide $3 + n$ by $1$ .

$3 + n < \frac{- 32}{- 4}$

Simplify the right side.

Divide $- 32$ by $- 4$ .

$3 + n < 8$

Step 2

Move all terms not containing $n$ to the right side of the inequality.

Subtract $3$ from both sides of the inequality.

$n < 8 - 3$

Subtract $3$ from $8$ .

$n < 5$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$n < 5$

Interval Notation:

$(- \infty, 5)$

Solve for n -4(3+n)>-32

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