Solve for n 4(n+2)-2n=0

$4 (n + 2) - 2 n = 0$

Simplify $4 (n + 2) - 2 n$ .

Simplify each term.

Apply the distributive property.

$4 n + 4 \cdot 2 - 2 n = 0$

Multiply $4$ by $2$ .

$4 n + 8 - 2 n = 0$

Subtract $2 n$ from $4 n$ .

$2 n + 8 = 0$

Subtract $8$ from both sides of the equation.

$2 n = - 8$

Divide each term in $2 n = - 8$ by $2$ and simplify.

Divide each term in $2 n = - 8$ by $2$ .

$\frac{2 n}{2} = \frac{- 8}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 n}{2} = \frac{- 8}{2}$

Divide $n$ by $1$ .

$n = \frac{- 8}{2}$

Simplify the right side.

Divide $- 8$ by $2$ .

$n = - 4$