Solve for n -41=-2/5(45n+60)+n

$- 41 = - \frac{2}{5} (45 n + 60) + n$

Rewrite the equation as $- \frac{2}{5} \cdot (45 n + 60) + n = - 41$ .

$- \frac{2}{5} \cdot (45 n + 60) + n = - 41$

Simplify $- \frac{2}{5} \cdot (45 n + 60) + n$ .

Simplify each term.

Apply the distributive property.

$- \frac{2}{5} (45 n) - \frac{2}{5} \cdot 60 + n = - 41$

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{2}{5}$ into the numerator.

$\frac{- 2}{5} (45 n) - \frac{2}{5} \cdot 60 + n = - 41$

Factor $5$ out of $45 n$ .

$\frac{- 2}{5} (5 (9 n)) - \frac{2}{5} \cdot 60 + n = - 41$

Cancel the common factor.

$\frac{- 2}{5} (5 (9 n)) - \frac{2}{5} \cdot 60 + n = - 41$

Rewrite the expression.

$- 2 (9 n) - \frac{2}{5} \cdot 60 + n = - 41$

Multiply $9$ by $- 2$ .

$- 18 n - \frac{2}{5} \cdot 60 + n = - 41$

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{2}{5}$ into the numerator.

$- 18 n + \frac{- 2}{5} \cdot 60 + n = - 41$

Factor $5$ out of $60$ .

$- 18 n + \frac{- 2}{5} \cdot (5 (12)) + n = - 41$

Cancel the common factor.

$- 18 n + \frac{- 2}{5} \cdot (5 \cdot 12) + n = - 41$

Rewrite the expression.

$- 18 n - 2 \cdot 12 + n = - 41$

Multiply $- 2$ by $12$ .

$- 18 n - 24 + n = - 41$

Add $- 18 n$ and $n$ .

$- 17 n - 24 = - 41$

Move all terms not containing $n$ to the right side of the equation.

Add $24$ to both sides of the equation.

$- 17 n = - 41 + 24$

Add $- 41$ and $24$ .

$- 17 n = - 17$

Divide each term in $- 17 n = - 17$ by $- 17$ and simplify.

Divide each term in $- 17 n = - 17$ by $- 17$ .

$\frac{- 17 n}{- 17} = \frac{- 17}{- 17}$

Simplify the left side.

Cancel the common factor of $- 17$ .

Cancel the common factor.

$\frac{- 17 n}{- 17} = \frac{- 17}{- 17}$

Divide $n$ by $1$ .

$n = \frac{- 17}{- 17}$

Simplify the right side.

Divide $- 17$ by $- 17$ .

$n = 1$

Solve for n -41=-2/5(45n+60)+n

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