Solve for n (4n-8)/(n-2)=n+2a

$\frac{4 n - 8}{n - 2} = n + 2 a$

Step 1

Factor each term.

Factor $4$ out of $4 n - 8$ .

Factor $4$ out of $4 n$ .

$\frac{4 (n) - 8}{n - 2} = n + 2 a$

Factor $4$ out of $- 8$ .

$\frac{4 n + 4 \cdot - 2}{n - 2} = n + 2 a$

Factor $4$ out of $4 n + 4 \cdot - 2$ .

$\frac{4 (n - 2)}{n - 2} = n + 2 a$

Reduce the expression by cancelling the common factors.

Reduce the expression $\frac{4 (n - 2)}{n - 2}$ by cancelling the common factors.

Cancel the common factor.

$\frac{4 (n - 2)}{n - 2} = n + 2 a$

Rewrite the expression.

$\frac{4}{1} = n + 2 a$

Divide $4$ by $1$ .

$4 = n + 2 a$

Step 2

Solve the equation.

Rewrite the equation as $n + 2 a = 4$ .

$n + 2 a = 4$

Subtract $2 a$ from both sides of the equation.

$n = 4 - 2 a$