Solve for n 5-2(n+2)=4+n

$5 - 2 (n + 2) = 4 + n$

Step 1

Simplify $5 - 2 (n + 2)$ .

Simplify each term.

Apply the distributive property.

$5 - 2 n - 2 \cdot 2 = 4 + n$

Multiply $- 2$ by $2$ .

$5 - 2 n - 4 = 4 + n$

Subtract $4$ from $5$ .

$- 2 n + 1 = 4 + n$

Step 2

Move all terms containing $n$ to the left side of the equation.

Subtract $n$ from both sides of the equation.

$- 2 n + 1 - n = 4$

Subtract $n$ from $- 2 n$ .

$- 3 n + 1 = 4$

Step 3

Move all terms not containing $n$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$- 3 n = 4 - 1$

Subtract $1$ from $4$ .

$- 3 n = 3$

Step 4

Divide each term in $- 3 n = 3$ by $- 3$ and simplify.

Divide each term in $- 3 n = 3$ by $- 3$ .

$\frac{- 3 n}{- 3} = \frac{3}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 n}{- 3} = \frac{3}{- 3}$

Divide $n$ by $1$ .

$n = \frac{3}{- 3}$

Simplify the right side.

Divide $3$ by $- 3$ .

$n = - 1$