Solve for n 6+9/7n=24

$6 + \frac{9}{7} n = 24$

Step 1

Combine $\frac{9}{7}$ and $n$ .

$6 + \frac{9 n}{7} = 24$

Step 2

Move all terms not containing $n$ to the right side of the equation.

Subtract $6$ from both sides of the equation.

$\frac{9 n}{7} = 24 - 6$

Subtract $6$ from $24$ .

$\frac{9 n}{7} = 18$

Step 3

Multiply both sides of the equation by $\frac{7}{9}$ .

$\frac{7}{9} \cdot \frac{9 n}{7} = \frac{7}{9} \cdot 18$

Step 4

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{7}{9} \cdot \frac{9 n}{7}$ .

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7}{9} \cdot \frac{9 n}{7} = \frac{7}{9} \cdot 18$

Rewrite the expression.

$\frac{1}{9} (9 n) = \frac{7}{9} \cdot 18$

Cancel the common factor of $9$ .

Factor $9$ out of $9 n$ .

$\frac{1}{9} (9 (n)) = \frac{7}{9} \cdot 18$

Cancel the common factor.

$\frac{1}{9} (9 n) = \frac{7}{9} \cdot 18$

Rewrite the expression.

$n = \frac{7}{9} \cdot 18$

Simplify the right side.

Simplify $\frac{7}{9} \cdot 18$ .

Cancel the common factor of $9$ .

Factor $9$ out of $18$ .

$n = \frac{7}{9} \cdot (9 (2))$

Cancel the common factor.

$n = \frac{7}{9} \cdot (9 \cdot 2)$

Rewrite the expression.

$n = 7 \cdot 2$

Multiply $7$ by $2$ .

$n = 14$