Solve for n 8x-10=-2(nx+-8)

$8 x - 10 = - 2 (n x + - 8)$

Replace all occurrences of $+$ $-$ with a single $-$ . A plus sign followed by a minus sign has the same mathematical meaning as a single minus sign because $1 \cdot - 1 = - 1$

$8 x - 10 = - 2 (n x - 8)$

Rewrite the equation as $- 2 (n x - 8) = 8 x - 10$ .

$- 2 (n x - 8) = 8 x - 10$

Divide each term in $- 2 (n x - 8) = 8 x - 10$ by $- 2$ and simplify.

Divide each term in $- 2 (n x - 8) = 8 x - 10$ by $- 2$ .

$\frac{- 2 (n x - 8)}{- 2} = \frac{8 x}{- 2} + \frac{- 10}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 (n x - 8)}{- 2} = \frac{8 x}{- 2} + \frac{- 10}{- 2}$

Divide $n x - 8$ by $1$ .

$n x - 8 = \frac{8 x}{- 2} + \frac{- 10}{- 2}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $8$ and $- 2$ .

Factor $2$ out of $8 x$ .

$n x - 8 = \frac{2 (4 x)}{- 2} + \frac{- 10}{- 2}$

Move the negative one from the denominator of $\frac{4 x}{- 1}$ .

$n x - 8 = - 1 \cdot (4 x) + \frac{- 10}{- 2}$

Rewrite $- 1 \cdot (4 x)$ as $- (4 x)$ .

$n x - 8 = - (4 x) + \frac{- 10}{- 2}$

Multiply $4$ by $- 1$ .

$n x - 8 = - 4 x + \frac{- 10}{- 2}$

Divide $- 10$ by $- 2$ .

$n x - 8 = - 4 x + 5$

Move all terms not containing $n$ to the right side of the equation.

Add $8$ to both sides of the equation.

$n x = - 4 x + 5 + 8$

Add $5$ and $8$ .

$n x = - 4 x + 13$

Divide each term in $n x = - 4 x + 13$ by $x$ and simplify.

Divide each term in $n x = - 4 x + 13$ by $x$ .

$\frac{n x}{x} = \frac{- 4 x}{x} + \frac{13}{x}$

Simplify the left side.

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{n x}{x} = \frac{- 4 x}{x} + \frac{13}{x}$

Divide $n$ by $1$ .

$n = \frac{- 4 x}{x} + \frac{13}{x}$

Simplify the right side.

Cancel the common factor of $x$ .

Cancel the common factor.

$n = \frac{- 4 x}{x} + \frac{13}{x}$

Divide $- 4$ by $1$ .

$n = - 4 + \frac{13}{x}$

Solve for n 8x-10=-2(nx+-8)

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