Solve for n d+3n=1

$d + 3 n = 1$

Step 1

Subtract $d$ from both sides of the equation.

$3 n = 1 - d$

Step 2

Divide each term in $3 n = 1 - d$ by $3$ and simplify.

Divide each term in $3 n = 1 - d$ by $3$ .

$\frac{3 n}{3} = \frac{1}{3} + \frac{- d}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 n}{3} = \frac{1}{3} + \frac{- d}{3}$

Divide $n$ by $1$ .

$n = \frac{1}{3} + \frac{- d}{3}$

Simplify the right side.

Move the negative in front of the fraction.

$n = \frac{1}{3} - \frac{d}{3}$