Solve for n g(n)=-2n-4

$g (n) = - 2 n - 4$

Step 1

Add $2 n$ to both sides of the equation.

$g n + 2 n = - 4$

Step 2

Factor $n$ out of $g n + 2 n$ .

Factor $n$ out of $g n$ .

$n g + 2 n = - 4$

Factor $n$ out of $2 n$ .

$n g + n \cdot 2 = - 4$

Factor $n$ out of $n g + n \cdot 2$ .

$n (g + 2) = - 4$

Step 3

Divide each term in $n (g + 2) = - 4$ by $g + 2$ and simplify.

Divide each term in $n (g + 2) = - 4$ by $g + 2$ .

$\frac{n (g + 2)}{g + 2} = \frac{- 4}{g + 2}$

Simplify the left side.

Cancel the common factor of $g + 2$ .

Cancel the common factor.

$\frac{n (g + 2)}{g + 2} = \frac{- 4}{g + 2}$

Divide $n$ by $1$ .

$n = \frac{- 4}{g + 2}$

Simplify the right side.

Move the negative in front of the fraction.

$n = - \frac{4}{g + 2}$