Solve for n log of n=4 log of 2

$\log (n) = 4 \log (2)$

Step 1

Simplify $4 \log (2)$ by moving $4$ inside the logarithm.

$\log (n) = \log (2^{4})$

Step 2

For the equation to be equal, the argument of the logarithms on both sides of the equation must be equal.

$n = 2^{4}$

Step 3

Raise $2$ to the power of $4$ .

$n = 16$