Solve for n (n5)4=(45)2

$(n \cdot 5) \cdot 4 = (4 \cdot 5) \cdot 2$

Simplify.

Multiply $4$ by $5$ .

$n \cdot 20 = 4 \cdot 5 \cdot 2$

Multiply $4$ by $5$ .

$n \cdot 20 = 20 \cdot 2$

Multiply $20$ by $2$ .

$n \cdot 20 = 40$

Divide each term in $(n \cdot 20) = 40$ by $20$ and simplify.

Divide each term in $(n \cdot 20) = 40$ by $20$ .

$\frac{(n \cdot 20)}{20} = \frac{40}{20}$

Simplify the left side.

Cancel the common factor of $20$ .

Cancel the common factor.

$\frac{n \cdot 20}{20} = \frac{40}{20}$

Divide $n$ by $1$ .

$n = \frac{40}{20}$

Simplify the right side.

Divide $40$ by $20$ .

$n = 2$

Solve for n (n*5)*4=(4*5)*2