Solve for n n+(n+1)+(n+1+1)=27

$n + (n + 1) + (n + 1 + 1) = 27$

Step 1

Simplify $n + n + 1 + n + 1 + 1$ .

Add $n$ and $n$ .

$2 n + 1 + n + 1 + 1 = 27$

Add $2 n$ and $n$ .

$3 n + 1 + 1 + 1 = 27$

Simplify by adding numbers.

Add $1$ and $1$ .

$3 n + 2 + 1 = 27$

Add $2$ and $1$ .

$3 n + 3 = 27$

Step 2

Move all terms not containing $n$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$3 n = 27 - 3$

Subtract $3$ from $27$ .

$3 n = 24$

Step 3

Divide each term in $3 n = 24$ by $3$ and simplify.

Divide each term in $3 n = 24$ by $3$ .

$\frac{3 n}{3} = \frac{24}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 n}{3} = \frac{24}{3}$

Divide $n$ by $1$ .

$n = \frac{24}{3}$

Simplify the right side.

Divide $24$ by $3$ .

$n = 8$