Solve for n t(n)=-8-7(n-1)

$t (n) = - 8 - 7 (n - 1)$

Step 1

Simplify $- 8 - 7 (n - 1)$ .

Simplify each term.

Apply the distributive property.

$t n = - 8 - 7 n - 7 \cdot - 1$

Multiply $- 7$ by $- 1$ .

$t n = - 8 - 7 n + 7$

Add $- 8$ and $7$ .

$t n = - 7 n - 1$

Step 2

Add $7 n$ to both sides of the equation.

$t n + 7 n = - 1$

Step 3

Factor $n$ out of $t n + 7 n$ .

Factor $n$ out of $t n$ .

$n t + 7 n = - 1$

Factor $n$ out of $7 n$ .

$n t + n \cdot 7 = - 1$

Factor $n$ out of $n t + n \cdot 7$ .

$n (t + 7) = - 1$

Step 4

Divide each term in $n (t + 7) = - 1$ by $t + 7$ and simplify.

Divide each term in $n (t + 7) = - 1$ by $t + 7$ .

$\frac{n (t + 7)}{t + 7} = \frac{- 1}{t + 7}$

Simplify the left side.

Cancel the common factor of $t + 7$ .

Cancel the common factor.

$\frac{n (t + 7)}{t + 7} = \frac{- 1}{t + 7}$

Divide $n$ by $1$ .

$n = \frac{- 1}{t + 7}$

Simplify the right side.

Move the negative in front of the fraction.

$n = - \frac{1}{t + 7}$