Solve for n2 ((n_1-n_2)m)/9=y

$\frac{(n_{1} - n_{2}) m}{9} = y$

Step 1

Multiply both sides by $9$ .

$\frac{(n_{1} - n_{2}) m}{9} \cdot 9 = y \cdot 9$

Step 2

Simplify.

Simplify the left side.

Simplify $\frac{(n_{1} - n_{2}) m}{9} \cdot 9$ .

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{(n_{1} - n_{2}) m}{9} \cdot 9 = y \cdot 9$

Rewrite the expression.

$(n_{1} - n_{2}) m = y \cdot 9$

Apply the distributive property.

$n_{1} m - n_{2} m = y \cdot 9$

Simplify the expression.

Reorder $n_{1}$ and $m$ .

$m n_{1} - n_{2} m = y \cdot 9$

Move $n_{2}$ .

$m n_{1} - 1 m n_{2} = y \cdot 9$

Simplify the right side.

Move $9$ to the left of $y$ .

$m n_{1} - 1 m n_{2} = 9 y$

Step 3

Solve for $n_{1}$ .

Rewrite $- 1 m$ as $- m$ .

$m n_{1} - m n_{2} = 9 y$

Add $m n_{2}$ to both sides of the equation.

$m n_{1} = 9 y + m n_{2}$

Divide each term in $m n_{1} = 9 y + m n_{2}$ by $m$ and simplify.

Divide each term in $m n_{1} = 9 y + m n_{2}$ by $m$ .

$\frac{m n_{1}}{m} = \frac{9 y}{m} + \frac{m n_{2}}{m}$

Simplify the left side.

Cancel the common factor of $m$ .

Cancel the common factor.

$\frac{m n_{1}}{m} = \frac{9 y}{m} + \frac{m n_{2}}{m}$

Divide $n_{1}$ by $1$ .

$n_{1} = \frac{9 y}{m} + \frac{m n_{2}}{m}$

Simplify the right side.

Cancel the common factor of $m$ .

Cancel the common factor.

$n_{1} = \frac{9 y}{m} + \frac{m n_{2}}{m}$

Divide $n_{2}$ by $1$ .

$n_{1} = \frac{9 y}{m} + n_{2}$