Solve for p -11+10(p+10)=4-5(2p+11)

$- 11 + 10 (p + 10) = 4 - 5 (2 p + 11)$

Step 1

Simplify $- 11 + 10 (p + 10)$ .

Simplify each term.

Apply the distributive property.

$- 11 + 10 p + 10 \cdot 10 = 4 - 5 (2 p + 11)$

Multiply $10$ by $10$ .

$- 11 + 10 p + 100 = 4 - 5 (2 p + 11)$

Add $- 11$ and $100$ .

$10 p + 89 = 4 - 5 (2 p + 11)$

Step 2

Simplify $4 - 5 (2 p + 11)$ .

Simplify each term.

Apply the distributive property.

$10 p + 89 = 4 - 5 (2 p) - 5 \cdot 11$

Multiply $2$ by $- 5$ .

$10 p + 89 = 4 - 10 p - 5 \cdot 11$

Multiply $- 5$ by $11$ .

$10 p + 89 = 4 - 10 p - 55$

Subtract $55$ from $4$ .

$10 p + 89 = - 10 p - 51$

Step 3

Move all terms containing $p$ to the left side of the equation.

Add $10 p$ to both sides of the equation.

$10 p + 89 + 10 p = - 51$

Add $10 p$ and $10 p$ .

$20 p + 89 = - 51$

Step 4

Move all terms not containing $p$ to the right side of the equation.

Subtract $89$ from both sides of the equation.

$20 p = - 51 - 89$

Subtract $89$ from $- 51$ .

$20 p = - 140$

Step 5

Divide each term in $20 p = - 140$ by $20$ and simplify.

Divide each term in $20 p = - 140$ by $20$ .

$\frac{20 p}{20} = \frac{- 140}{20}$

Simplify the left side.

Cancel the common factor of $20$ .

Cancel the common factor.

$\frac{20 p}{20} = \frac{- 140}{20}$

Divide $p$ by $1$ .

$p = \frac{- 140}{20}$

Simplify the right side.

Divide $- 140$ by $20$ .

$p = - 7$

Solve for p -11+10(p+10)=4-5(2p+11)

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