Solve for p 13+3p+10=23+3p

$13 + 3 p + 10 = 23 + 3 p$

Step 1

Add $13$ and $10$ .

$3 p + 23 = 23 + 3 p$

Step 2

Move all terms containing $p$ to the left side of the equation.

Subtract $3 p$ from both sides of the equation.

$3 p + 23 - 3 p = 23$

Combine the opposite terms in $3 p + 23 - 3 p$ .

Subtract $3 p$ from $3 p$ .

$0 + 23 = 23$

Add $0$ and $23$ .

$23 = 23$

Step 3

Since $23 = 23$ , the equation will always be true for any value of $p$ .

All real numbers

Step 4

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$