Solve for p 144-p^2=0

$144 - p^{2} = 0$

Subtract $144$ from both sides of the equation.

$- p^{2} = - 144$

Divide each term in $- p^{2} = - 144$ by $- 1$ and simplify.

Divide each term in $- p^{2} = - 144$ by $- 1$ .

$\frac{- p^{2}}{- 1} = \frac{- 144}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{p^{2}}{1} = \frac{- 144}{- 1}$

Divide $p^{2}$ by $1$ .

$p^{2} = \frac{- 144}{- 1}$

Simplify the right side.

Divide $- 144$ by $- 1$ .

$p^{2} = 144$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$p = \pm \sqrt{144}$

Simplify $\pm \sqrt{144}$ .

Rewrite $144$ as $12^{2}$ .

$p = \pm \sqrt{12^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$p = \pm 12$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$p = 12$

Next, use the negative value of the $\pm$ to find the second solution.

$p = - 12$

The complete solution is the result of both the positive and negative portions of the solution.

$p = 12, - 12$